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Sever21 [200]
3 years ago
13

Which substance would most neutralize an acidic food?

Biology
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

<u>Option-(D):</u>The substance which is the most likely to neutralize the acidic food or substance is the baking soda (pH 8-9).

Explanation:

As, the baking soda having a p.H of about 8-9 is able to neutralize the acidic food or substance more effectively. Along, with which we all know that there is given scale for each of the substance on the scale of being either acidic(p.H is less then 7),basic(p.H is more then 7) , or being a neutral substance(p.H= 7). While, different substances are well equipped to neutralize each other's effects more effectively.

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Which of the following correctly identifies the main function of photosynthesis?
Liono4ka [1.6K]

Answer: The correct answer is- Converts solar energy to chemical energy.

Photosynthesis is a process of formation of food by green plants and algae using CO₂ and H₂O in the presence of sunlight. In this process, energy from sunlight is absorbed by chlorophyll ( green pigment present in the chloroplast) and it is converted into chemical energy in the form of ATP and NADPH. This is further utilized in the formation of food that is a carboydrate ( glucose).


5 0
3 years ago
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You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

4 0
3 years ago
Which of the following BEST describes the process of evolution?
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C. Gradual

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In which process do plants release oxygen?
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Photosynthesis is your answer :)))

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