Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
+x on each side. Then -2 on each side. Then divide both sides by 6 and you have your answer
When the X term is one, and doesn't have a leading coefficient, then you can factor it using the box and diamond method. look up videos on Khan Academy of the box and diamond method for solving trinomials. For number 9, you have a difference of squares. That means you can factor to just 2 terms. (x+4)(x-4) this works because 16 has an easy square root, and the sign in between is a negative(difference)
Answer:
The objective of the problem is obtained below:
From the information, an urn consists of, 4 black, 2 orange balls and 8 white.
The person loses $1 for each white ball selected, no money is lost or gained for any orange balls picked and win $2 for each black ball selected. Let the random variable X denotes the winnings.
No winnings probability= 0.011
Probability of winning $1=0.3516
Probability of winning $2= 0.0879
Probability of winning $4= 0.0659
Answer:
Cube
Step-by-step explanation:
It makes a cube