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disa [49]
3 years ago
6

9×(30+7)=(9×___)+(9×7)

Mathematics
1 answer:
natta225 [31]3 years ago
8 0
The blank is 30

the property there using is distributive property.
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FOR BRAINLIEST<br> А is equivalent to 0.001 grams.<br> milligram<br> kilogram<br> decigram
tatiyna

Answer:

The answer is milligram, glad to help

Step-by-step explanation:

6 0
3 years ago
Which of the following sets of numbers could be the lengths of the sides of a triangle?
Oksanka [162]
B. 3ft, 4ft, 5ft

Pythagoras' Theorem where the square of the two smaller sides added together equals the square of the hypotenuse. If the two smaller sides are 3 and 4 then the hypotenuse is always going to be 5
7 0
3 years ago
(a) For the accompanying data set, draw a scatter diagram of the data.
lidiya [134]

Answer:

a) n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

b) Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0  

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y.

And the reason is because we fail to reject the null hypothesis.

Step-by-step explanation:

Part a

We have the following data:

x: 2  6  6  7  9

y: 3  2  6  9  5

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

Part b

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degreed of freedom. df=n-2=5-2=3

In our case the value for the statistic would be:

t=\frac{0.430\sqrt{5-2}}{\sqrt{1-(0.430)^2}}=0.825

The critical value for n =5 is given by the table attached. We can see that the critical value is r_{crit}= 0.878, and then the final conclusion would be:

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y

And the reason is because we fail to reject the null hypothesis.

4 0
2 years ago
May someone help me out with this please please
ycow [4]
P(A)=\dfrac{5}{12}
6 0
3 years ago
Solve for y<br> x+y= -15
Illusion [34]

X + y = -15. Subtract x from both sides.

y = -x - 15. This is as far as we can go with the provided information.

5 0
3 years ago
Read 2 more answers
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