3 ft 3 ft O What is the surface area of the 3-dimensio shape?

Find the maximum value of the function <img src="https://tex.z-dn.net/?f=%20-%208%20%2B%202x%20-%204x%20%5E%7B2%7D%20" id="T

Mkey [24]

Answer:

x = $\frac{-b}{2a}$

Step-by-step explanation:

Start by using P.E.M.D.A.S.

-8 is a 2x is b and -4 $x^{2}$ is c.

7 0

3 years ago

The volume of a cube is 1.8 m3. Find the length of its edge to the nearest tenth of a

Firdavs [7]

The length of an edge is the cubic root of the volume.

Cubic root 1.8 = 1.2 meters

5 0

2 years ago

Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan

SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola. The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60. So the garden should be 20 ft by 60 ft.

4 0

2 years ago

What is the perimeter of this figure

lesantik [10]

Answer:

11+11+3+3+3= 31

Step-by-step explanatio

7 0

3 years ago

Read 2 more answers

Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat

SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Reasoning in the same way:

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b) Now want to know when the two pools would have the same amount of water. If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

5 0

3 years ago

3 ft3 ftO What is the surface area of the 3-dimensioshape?