Answer:
C. Triangle BAC is congruent to triangle FDE by AAS
Step-by-step explanation:
BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.
The only viable answer choice is C.
No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.
Answer: Only Ingrid
Step-by-step explanation:
To find the perimeter you do length + width so you do 12.4 + 5.9 to get the perimeter.
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that
a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3
Answer:
-1, 8 hope this helps good luck
