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mojhsa [17]
3 years ago
15

What is the perimeter of the figure? A. 144 cm B. 76 cm C. 74 cm D. 45 cm

Mathematics
2 answers:
tatiyna3 years ago
8 0
76 cm would be your answer, so B.
USPshnik [31]3 years ago
3 0
I believe it's B - 76 cm. (:
I hope all is well, and you end up passing!
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Multiple choice plz plz help! Thanks:)
Minchanka [31]
A- Since the radius is 22, the area is 1520.53, or, 1520.5 simplified.
3 0
3 years ago
Margaret grew apples on a portion of her garden last year. She intends to reduce the length of each side of the portion of her g
ollegr [7]
Redued by 15%

orignal=100%
decrease by 15%=100%-15%=85%

find 85% of original
orignal=15 feet

85% of 15=0.85 times 15=12.75 feet

answer is B
7 0
2 years ago
HELP PLEASE WILL CROWN BRAINLIEST!!
liubo4ka [24]

Answer:

-18 C°

Step-by-step explanation:

Warmed means add cooled means subtract

starting at -23 it warmed by 8 add 8

-15

it warmed by 3 more add 3

-12

then it cooled by 6 subtract 6

-18

8 0
2 years ago
Write a phrase for each expression.
AveGali [126]

Step-by-step explanation:

HERE

* 11x

Phrase= x times 11

Operation= times

* 8-y

Phrase= 8 minus y

Operation = minus

1- 7n

2- 4-y

3- 13 + x

4- x divided by 12

5- y times 10

6- c added to 3

4 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
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