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storchak [24]
2 years ago
14

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B

Mathematics
1 answer:
JulsSmile [24]2 years ago
5 0

Answer:

They will do rounds together again in 11 minutes and 40 seconds.

Step-by-step explanation:

Security A rounds every 2 minutes and 20 seconds in the gate 1.

That is, after 2*60 + 20 = 120 + 20 = 140 seconds.

Security B rounds every 1 minute and 40 seconds in the gate 2.

That is, after 1*60 + 40 = 60 + 40 = 100 seconds.

After how many minutes they will rounds together again?

First, we find this is seconds, which is the least common multiple between 140 and 100. Factoring them by prime factors:

140 - 100|2

70 - 50|2

35 - 25|5

7 - 5|5

7 - 1|7

1 - 1

lcm(140,100) = 2*2*5*5*7 = 700 seconds

They will do rounds together again in 700 seconds, which is 11 minutes and 40 seconds.

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Answer:

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Step-by-step explanation:

1) Find out what are the factors of the constant?

2) Which of those add to equal the coefficient before the x value?

In this particular equation, we have the constant being 24. The first two factors that come to mind are 6 and 4, and 8 and 3. Since it is -24, we need one of these numbers to be negative.

Let's look at our "b" value, or the coefficient behind the x value, 5. Looking at our factors and thinking of addition (since one of them must be negative, it will most likely be subtraction instead of addition) I can see that

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Answer:

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