Answer:
-2
The problem:
y=f(x)=x^2+x
find the slope of the secant line joining (-3,f(-3)) and (0,f(0))
Step-by-step explanation:
We need to first find the values that correspond to f(-3) and f(0).
f(-3) can be found by replacing the x's in f(x)=x^2+x with (-3):
f(-3)=(-3)^2+(-3)
f(-3)=9+-3
f(-3)=6
f(0) can be found by replacing the x's in f(x)=x^2+x with (0):
f(0)=(0)^2+(0)
f(0)=0+0
f(0)=0
So we want to find the slope of the line going through the points:
(-3,6) and (0,0)
Line them up-doesn't matter which point goes on top:
(-3,6)
(0,0)
---------Now subtract!
-3 , 6
The rise goes over the run so the slope is 6/-3 which simplifies to -2.
