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3 years ago

Solve 16(3x-5) -10(4x-8) = 40

Mathematics

2 answers:

nydimaria [60]3 years ago

6 0

Answer:

x = 5

Step-by-step explanation:

Step 1: Multiply out the brackets

48x - 80 - 40x + 80 = 40 → negative + negative = positive [-10 x -8]

Step 2: Simplify

8x = 40 → collect like terms

Step 3: Solve

x = (40/8)

x = 5

Mashcka [7]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

Step 1: Multiply out the brackets

48x - 80 - 40x + 80 = 40 → negative + negative = positive [-10 x -8]

Step 2: Simplify

8x = 40 → collect like terms

Step 3: Solve

x = $\frac{40}{8}$

x = 5

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A section of concrete pipe 30m long has an inside diameter of 1.2m and an outside diameter of 1.8m. what is the volume of concre

Fudgin [204]

length of pipe= 30m

Inside dia. = 1.2m

Outside dia. = 1.8m

Volume of concrete= (outside dia. - inside dia.)h

V= (pi)
v= [(3.14*0.9*0.9)-(3.14*0.6*0.6)]30

v= (3.3534-1.1304)30
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since it's volume the answer 66.690 is in cubic meters.

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3 years ago

Identify each function that has a remainder of -3 when divided x+6

Sergeu [11.5K]

Answer:

Step-by-step explanation:

According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.

So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.

For A:

$x^5 + 2x^2 - 30x + 30\\=(-6)^5 + 2(-6)^2 - 30(-6) + 30\\=-7494$

For B:

$x^4 + 4x^3 - 21x^2 - 53x + 12\\=(-6)^4 + 4(-6)^3 - 21(-6)^2 - 53(-6) + 12\\=6$

For C:

$x^3 - 10x^2 - 7\\=(-6)^3 - 10(-6)^2 - 7\\=-583$

For D:

$x^4 + 6x^3 - 10x - 63\\=(-6)^4 + 6(-6)^3 - 10(-6) - 63\\=-3$

The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.

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2 years ago

What is the simplest way to explain scale drawings for middle school math?

Allushta [10]

Answer:

The simplest way to teach middle school math scale drawings is to use real pictures to relate to each other to explain the concept. For example, scaling a red ball of 1" to a ball of 2" and so on. This will show how the ball increases by size by adding 1" each time.

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2 years ago

4sinθ – 1 = - 3 for 0<θ< 360

EastWind [94]

Answer:

$\theta = 210^\circ$ or $\theta = 330^\circ$

Step-by-step explanation:

$4 \sin \theta - 1 = -3$

$4 \sin \theta = -2$

$\sin \theta = \dfrac{-2}{4}$

$\sin \theta = -0.5$

For sin θ = 0.5, the reference angle is θ = 30 deg.

$\sin 30^\circ = 0.5$

$\theta = 210^\circ$ or $\theta = 330^\circ$

7 0

3 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

marishachu [46]

Answer:

$\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

Step-by-step explanation:

We have been given the function

$f(x)=-2x^2+4x^3+3x^2+18$

From the rational zeros theorem, we have

$\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}$

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

$\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

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3 years ago