D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Are there any answer choices ?
Answer:
7, 4ft
Step-by-step explanation:
Given data
area = 108 square feet
length = (x-1)
width = (x-4)
Area=L*W
open bracket
a= 1
b=-5
c=-104
Applying the quadratic formula
x=-13
or
x=8
since x cannot be negative
x= 8
length = (x-1)= 8-1= 7ft
width = (x-4)= 8-4= 4ft
Answer:
23
Step-by-step explanation:
Answer:
9. the measure of DEF is 103°
10. the measure of DEG is 77°
11. 90°
Step-by-step explanation:
it's pretty simple, just take into consideration that the final measure of all the angles of a triangle must be 180°
