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Andreas93 [3]
3 years ago
14

Which is a requirement for searching for a template

Computers and Technology
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

umm... you did not discribe the anwsers, i cannot help you

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A line of text that has an equal number of characters on either side of the horizontal center of the page is called____.
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A) force justified.

If you open up Word (or probably any word processor) and hover over the alignment options in the ribbon (or format the paragraph), it tells you what each one is, and the option that ensures the characters are spread evenly between the margins is labeled "justified."
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The piece of hardware that contains the circuitry that processes the information coming into the computer and tells the other ha
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The central processing unit
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These operating systems were referred to as command-based.
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{\underline{\boxed{\bf{MS - DOS \:  and \:  UNIX}}}}

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What is the value of: 1 + int(3.5) / 2?<br> Select one:<br> a. 2<br> b. 2.25<br> C. 2.5<br> d. 3
Drupady [299]

Answer:

C (2.5)

Explanation:

int(3.5) = 3

So, using order of operations, (3/2)+1=2.5

8 0
3 years ago
a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d
BaLLatris [955]

Answer:

\frac{10!}{2}mins

Explanation:

12 seconds to try one combination will be equivalent to  \frac{1}{12}\times 60 = \frac{1}{5} \ mins

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to \frac{10!}{2}.

Total number of passwords combination possible for each position in 9 digit.  

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to \frac{10!}{1}.

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1.  Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by  \frac{1}{5} \ mins  to get the total number of time needed to guarantee access to database =  [\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}

7 0
3 years ago
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