Hi, thank you for posting your question here at Brainly.
The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
Step-by-step explanation:
in x ,y =0
in y ,x =0
i think its thik ok dont mind if its wrong
On Monday she made 50 throws.
On Tuesday she made 56 throws.
a) The increase is just how much more she made the next day.
56 - 50 = 6
She had an increase of 6 free throws.
b) To find the percent increase, all you do is divide the two numbers.
56/50 = 1.12
To change that into a percentage, either multiply it by 100 or move the decimal point two places to the right.
1.12 × 100 = 112
She had a 112% increase in her free throws.
The answer is:
D. 6; 112%
<span>2/5g+3h-6 when g=10 and h=6
</span><span>2/5 (10) +3(6) - 6
</span><span>= 4 + 18 - 6
= 16
</span>
