We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
If you want to learn more, you can read:
brainly.com/question/1349408
Answer:
+ 16
Step-by-step explanation:
x² - 8x = - 10
to complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 4)x + (- 4) = - 10 + (- 4)²
x² - 8x + 16 = - 10 + 16
thus 16 is added to both sides to complete the square
Hello! :)
The sum of the number of dogs and cats.
Cats= 6
Dogs= d
It is asking for the sum. (the number added together)
d+6 or "C" is the correct answer.
~'Manda
Let
x--------------> the number of slices eating by Consuela and her <span>three friends
we know that
[total slices]=8*2=16 slices
</span><span>[slices of pizza for her older brother]=2
x=16-2=14 slides
</span><span>Consuela and her friends share the rest of the pizza, each eating the same number of slices---------> 14/4= 3.5 slides of pizza each (</span><span>this part is not necessary, but it is shown in a didactic way)
</span><span>
the question is
</span><span>What fraction of the 2 pizzas is left over?
</span>[slices of pizza for her older brother]/[total slices]=2/16=1/8
<span>
the answer is (1/8)
</span>
