Ask question

Ask question

All categories

3 years ago

10

-162=-3+4(6 - 7x) A) (-10) B) {6} c) 3 D)-4)

1 answer:

Nookie1986 [14]3 years ago

6 0

The value of x is option B) 6.

<u>Step-by-step explanation:</u>

The given equation is -162=-3+4(6 - 7x).

You can see the bracket on the right of the equation. To remove the bracket, we must use the distributive property.

The distributive property is to multiply the number outside the bracket with each term present inside the bracket.

Here, the number outside the bracket is 4 ans we have to multiply it with 6 and -7x which are inside the bracket.

The simplified form is,

⇒ -162 = -3 + 24 - 28x

Keep x term alone on one side and bring all the constant terms to the other side of the equation.

⇒ -162 = 21 -28x

⇒ 28x = 21+162

⇒ 28x = 183

Divide by 28,

⇒ x = 183/28

⇒ x = 6.5

x can be approximated to 6 which is option B)

Therefore, the value of x is 6.

You might be interested in

What are the zeros of the quadratic function f(x)=8^2-16-15

Free_Kalibri [48]

Answer:

C)

Step-by-step explanation:

f(x)= $8x^{2} -16x-15$
$8x^{2} -16x-15=0$
$x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}$ , a=8, b= - 16, c= - 15

$x=\frac{-(-16)+-\sqrt{(-16)^2-4*8*(-15)} }{2*8} = \frac{16+-\sqrt{736} }{16} =\frac{16+-4\sqrt{46} }{16} = 1 +- \frac{\sqrt{46} }{4} = 1+- \frac{\sqrt{23} \sqrt{2}}{2\sqrt{2} \sqrt{2} } =1+-\frac{\sqrt{23} }{2\sqrt{2} } = 1+-\frac{\sqrt{23} }{\sqrt{8} }$

6 0

2 years ago

Write an equation of the cosine function with amplitude pi/2 and period 3

juin [17]

Answer:

$y = \frac{\pi}{2}cos(\frac{2\pi}{3}x)$

Step-by-step explanation:

Given

$Amplitude = \frac{\pi}{2}$

$Period = 3$

Required

Write the equivalent cosine function

The general formula is:

$y = acos(bx)$

Where

$amplitude = |a|$

$period = \frac{2\pi}{b}$

Substitute $\frac{\pi}{2}$ for amplitude in $amplitude = |a|$

$|a| = \frac{\pi}{2}$

$a = \frac{\pi}{2}$

Substitute 3 for period in $period = \frac{2\pi}{b}$

$\frac{2\pi}{b} = 3$

<em>Multiply both sides by b</em>

$2\pi = 3b$

<em>Divide through by 3</em>

$b = \frac{2\pi}{3}$

Hence;

$y = acos(bx)$ becomes

$y = \frac{\pi}{2}cos(\frac{2\pi}{3}x)$

5 0

3 years ago

Please help with this question!

IgorC [24]

Answer:

QR = 5

Step-by-step explanation:

Since the parallelograms are similar, then the ratios of corresponding sides are equal, that is

$\frac{AB}{PQ}$ = $\frac{BC}{QR}$ , then

$\frac{9}{3}$ = $\frac{15}{QR}$ ( cross- multiply )

9QR = 45 ( divide both sides by 9 )

QR = 5

8 0

3 years ago

Write the equation of the line through the points (2,4)(-3,-1). write answer in a point slope form

luda_lava [24]

Answer:

The point-slope form would be y - 4 = x - 2

Step-by-step explanation:

In order to find the equation of the line, we first need to find the slope. For that, we use the slope formula.

m (slope) = (y1 - y2)/(x1 - x2)

Now we plug the numbers into the equation.

m (slope) = (y1 - y2)/(x1 - x2)

m (slope) = (4 - -1)/(2 - -3)

m (slope) = 5/5

m (slope) = 1

Now we can use point-slope form along with the slope and either point to write the equation.

y - y1 = m(x - x1)

y - 4 = (x - 2)

3 0

3 years ago

Which equation is equivalent to x2+10x+2=0 ?

Svet_ta [14]

<span> x =(10-√92)/2=5-√ 23 = 0.204 or </span><span><span>x =(10+√92)/2=5+√ 23 = 9.796 </span> </span>

4 0

3 years ago