SOLUTION
Let the two integers be x and y.
Now, the product of x and y, is 80, that is

The quotient of x and y is 5, that is

From equation 2, make x, the subject, we have

Now substitute the x for 5y into equation 1, we have
![\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20xy%3D80%20%5C%5C%205y%5Ctimes%20y%3D80%20%5C%5C%205y%5E2%3D80%20%5C%5C%20%5Ctext%7Bdividing%20by%205%7D%20%5C%5C%20y%5E2%3D%5Cfrac%7B80%7D%7B5%7D%20%5C%5C%20y%5E2%3D16%20%5C%5C%20%5Ctext%7Btake%20square%20root%20of%20both%20sides%20%7D%20%5C%5C%20%5Csqrt%5B%5D%7By%5E2%7D%3D%5Csqrt%5B%5D%7B16%7D%20%5C%5C%20%5Ctext%7Bsquare%20cancels%20root%7D%20%5C%5C%20y%3D4%20%5Cend%7Bgathered%7D)
Now substitute y for 4 into any of the equations.
Let us use equation 1 again, we have

Hence the answer is 4, 20