Answer:
The correct answer to this question is: "this program give an error".
int i = 7; //declare a variable(i) and assign value.
while (i>=2) //use loop and check condition.i greater then equal to 2.
{
System.out.print (i +""); //print value of i.
if ((i%3) == 0) //hold remainder
{
i +2; //error.
}
else
{
i/=2; //hold Quotient
}
}
Explanation:
In the above program, there is an error in the if block because it is not the correct way to declare. To use the variable from the correct output we use a variable like this.
Example
int i = 7;
//declare a variable(i) and assign value.
while (i>=2)
//use loop and check condition.i greater then equal to 2.
{
System.out.print (i +""); //print value of i.
if ((i%3) == 0) //hold remainder
{
i =i+2;
}
else
{
i/=2; //hold Quotient
}
}
Output: 732
Answer:
oid changeCase (char char_array[], int array_size ) {
__asm{
mov eax, char_array;
mov edi, 0;
readArray:
cmp edi, array_size;
jge exit;
mov ebx, edi;
shl ebx, 2;
mov cl, [eax + ebx];
check:
//working on it
cmp cl, 0x41;
jl next_indx;
cmp cl, 0x7A;
jg next_indx;
cmp cl, 'a';
jl convert_down;
jge convert_up;
convert_down:
or cl, 0x20; //make it lowercase
jmp write;
convert_up:
and cl, 0x20;
jmp write;
write:
mov byte ptr [eax + ebx], cl
next_indx:
inc edi;
exit:
cmp edi, array_size;
jl readArray;
mov char_array, eax;
}
}
Explanation:
- Move char_array to eax as it is base image
.
- Use ebx as offset
.
- Use ecx as the storage register
.
- check if cl is <= than ASCII value 65 (A)
.
Answer:
here is your answer
Explanation:
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