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GuDViN [60]
3 years ago
14

Find the slope of the graph of the relation y^3 − xy = −6 at the point (7, 2).

Mathematics
1 answer:
mezya [45]3 years ago
5 0
Yay, implicit differnentiation

when you take the derivitive of y, you multiply it by dy/dx
example
dy/dx y^2=2y dy/dx

for x, the dy/dx dissapears

ok
so differnetiate and solve for dy/dx

3y² dy/dx-(y+x dy/dx)=0
expand
3y² dy/dx-y-x dy/dx=0
3y² dy/dx-x dy/dx=y
dy/dx (3y²-x)=y
dy/dx=y/(3y²-x)

so at (7,2)
x=7 and y=2
dy/dx=2/(3(2)²-7)
dy/dx=2/(3(4)-7)
dy/dx=2/(12-7)
dy/dx=2/5

answer is 2/5
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Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] < y0 < [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
2 years ago
The campsite is square in shape and has an area of 4225 m2. What is the length of the campsite?
ziro4ka [17]
65 x 65= 4,225 m²
hope it helps! (:

7 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!! SHOW YOUR WORK AND EXPLAIN WILL MARK BRAINIEST
NeTakaya

THE 147TH TERM IS C

I MULTIPLY 37 TO 4 WHICH IS EQUAL TO 148 WHICH IS D

SO  148 - 1 = 147 WHICH IS C

4 0
2 years ago
What percent of 1.60 is 6
JulsSmile [24]
N% x 1.60 = 6   (I turned it from English to math)
Can't move n% back two places to make it a decimal so I will move the number I am multiplying by n% back two places instead.
Here is a sample to show you why it works.    .34 x 57 = 34 x .57

So
.016n = 6   (.016 is 1.60 decimal moved back two places)

Now divide both sides by .016
<u>.016</u>n   = <u>6
</u><u />.016     .016      n = 375%     

Why is the percent over 100% you might ask?

What % of 1.60 is 1.60  (Answer - all of it or 100%)
So What % of 1.60 is 6  - the number 6 being much bigger than 1.60, it is not surprising that the percent is more than 100.

What % of 1.60 is 1.60  - 100%
What %  of 1.60 is 3.20 - 200%   (notice that 3.20 is twice 1.60)
What % of 1.6 is 4.80   - 300%   (notice that 4.80 is three times 1.60)
What % of 1.6 is  6.40   - 400%  (notice that  6.40 is four times 1.60)
6 (the number in the problem) is just a bit less than 6.40  so 375% makes a lot a sense.
Hope you found this helpful. 

6 0
3 years ago
8.
Umnica [9.8K]
The answer you are looking for is 12! have a great day!:)
6 0
3 years ago
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