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Naddik [55]
3 years ago
12

Before a sale, an item’s price was $28.00. After the sale discount the price became $21.00. What was the percent of the sale dis

count?
Mathematics
1 answer:
NARA [144]3 years ago
4 0
The discount was 25% off use 21/28 which is 75 percent of what it was before. 25 percent off.
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Find the perimeter of the figure <br> 13.5 ft<br> 9 ft<br> 12.5 ft
saveliy_v [14]

Answer:

Add all the values up and then divide by 2

Step-by-step explanation:

5 0
3 years ago
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Need some help working these out
s2008m [1.1K]

Answers:

  • Problem 1)  40 degrees
  • Problem 2) 84 degrees
  • Problem 3) 110 degrees

===============================================

Explanation:

For these questions, we'll use the inscribed angle theorem. This says that the inscribed angle is half the measure of the arc it cuts off. An inscribed angle is one where the vertex of the angle lies on the circle, as problem 1 indicates.

For problem 1, the arc measure is 80 degrees, so half that is 40. This is the measure of the unknown inscribed angle.

Problem 2 will have us work in reverse to double the inscribed angle 42 to get 84.

-------------------

For problem 3, we need to determine angle DEP. But first, we'll need Thales Theorem which is a special case of the inscribed angle theorem. This theorem states that if you have a semicircle, then any inscribed angle will always be 90 degrees. This is a handy way to form 90 degree angles if all you have is a compass and straightedge.

This all means that angle DEF is a right angle and 90 degrees.

So,

(angle DEP) + (angle PEF) = angle DEF

(angle DEP) + (35) = 90

angle DEP = 90 - 35

angle DEP = 55

The inscribed angle DEP cuts off the arc we want to find. Using the inscribed angle theorem, we double 55 to get 110 which is the measure of minor arc FD.

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3 years ago
(4.23)(1.6) please multiple
Wewaii [24]

Answer:

The correct answer is 6.768.

Step-by-step explanation:

(4.23)(1.6) = 6.768

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Solnce55 [7]

Answer:

$132.59 is the answer

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Divid 15 into two parts such that the sum of their reciprocal is 3/10
Klio2033 [76]
From the information obtained from the question, two equations can be created:
 
Let x and z be the two numbers (parts)

\frac{1}{z}   +   \frac{1}{x}  =   \frac{3}{10} .  .  .  . (1)

z  +   x  =  15  .  .  .  . (2)

By transposing (2), make 'z' the subject of the equation
z = 15 - x  .  .  .  . (3)

By substituting (3) into equation (1) to find a value for x
\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}

\frac{15}{( 15 - x ) ( x )}  =   \frac{3}{10}

3 ( - x^{2}  + 15 x )  =  150

3 x^{2}  - 45x + 150 = 0

⇒  ( x - 5 )  ( x - 10 )  = 0

∴ either ( x - 5) = 0        OR    ( x - 10 ) = 0

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

     z + (5) = 15       OR      z + (10) = 15

    ⇒      z = 10      OR                 z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.





5 0
3 years ago
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