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2 years ago

−4/9f=−3 Help I’m cool

Mathematics

1 answer:

lana66690 [7]2 years ago

4 0

Im pretty sure the answer is 6.750 but not 100% sure so you might get it wrong if you go with my answer

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What’s the equation for (8,2)(0,0)

Kay [80]

Answer: y=4x

Step-by-step explanation:

We will make use of the slope intercept form to solve this question:

First of all, we have to calculate the slope from the 2 points (8,2) and (0,0).

We know that the formula for the slope is: m = (y2 - y1) / (x2 - x1)

From the question, y2 = 0, y1 =2, x1 =8 and x2 = 0.

Therefore, slope (m) = (0 - 2)/(0 - 8)

This gives us m = 2/8 and simplified further to 1/4.

The slope intercept form of the equation is y = mx + c where "m" is the slope.

Therefore substituting the value of 1/4 for "m" in the equation, we get;

y = (x/4) + c

Now to get the value of "c",let's substitute the value of x and y from the first intercept of (8,2).

We get; 2 = (8/4) + c

; 2 = 2 + c

Subtract 2 from both sides to get c = 0.

Also, when we use the value of x and y from the second intercept (0,0), we get the same value of c=0

Therefore the equation for the 2 points are y = 4x + 0 which gives y=4x

4 0

3 years ago

What is the area of this figure?

lesantik [10]

Answer:

$\Huge\boxed {A =859ft^{2} }$

Step-by-step explanation:

Hello There!

To solve for the area of this figure we need to split the figure into 3 different parts:

A rectangle with a length of 9 ft and a width of 7 ft

a rectangle with a width of 9ft + 7ft and a length of 25 ft

a rectangle with a width of 18 ft and a length of 22 ft

To find the area of a rectangle we use the formula

$A=w*l$ where w = width and l = length

for the first one we plug in the values

A = 9 * 7

9 * 7 = 63 so the area of the smallest rectangle is 63ft²

Now lets find the area of the larger rectangle

The dimensions are l = 25 ft and w = 9 + 7 (16 ft)

Now we can plug in the values into the area formula

A = 16 * 25

16*25=400 so the area of the larger rectangle is 400 ft²

Now lets find the area of the last rectangle

The dimensions are l = 22 ft and w = 18 ft

now lets plug in the values to the formula

A = 22 * 18 =396

so the area of the last rectangle is 396 ft²

Finally we want to add all of the areas together

396 + 400 + 63 = 859

So the area of the figure is 859 ft²

7 0

3 years ago

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What is the degree measure of an interior angle of a regular pentagon?

satela [25.4K]

Answer:

it is 540 degrees.

Step-by-step explanation:

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3 years ago

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It takes 80 oz of grass seed to seed 5600 ft? of lawn. At this rate, how much would be needed for 8400 ft of lawn?

yarga [219]

Bgbfbtgfhrbrjrhfbrbthtbtutbit trinity

8 0

2 years ago

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If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.

Gnom [1K]

Answer: $\tan \theta=\dfrac{1}{\sqrt3}.$

Step-by-step explanation: Given that

$\sin\theta=-\dfrac{1}{2}$ and $\theta$ lies in Quadrant III.

We are to find the value of $\tan \theta.$

We will be using the following trigonometric identities:

$(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.$

We have

$\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.$

Since $\theta$ lies in Quadrant III, so tangent will be positive.

Thus,

$\tan \theta=\dfrac{1}{\sqrt3}.$

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3 years ago

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