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Free_Kalibri [48]
3 years ago
14

The two-way table shows the ages of the players on different soccer teams. A 6-column table has 4 rows. The first column has ent

ries 8 years old, 9 years old, 10 years old, Total. The second column is labeled Team A with entries 4, 9, 2, 15. The third column is labeled Team B with entries 6, 4, 3, 13. The fourth column is labeled Team C with entries 8, 3, 5, 16. The fifth column is labeled Team D with entries 3, 7, 4, 14. The sixth column is labeled Total with entries 21, 23, 14, 58. Which statement is true? The probability that a randomly selected player on Team A is 8 years old is StartFraction 4 Over 21 EndFraction. The probability that a randomly selected 8-year-old player is on Team C is StartFraction 16 Over 21 EndFraction. The probability that a randomly selected player on Team C is 10 years old is StartFraction 5 Over 16 EndFraction. The probability that a randomly selected 10-year-old player is on Team B is StartFraction 13 Over 58 EndFraction.
Mathematics
2 answers:
mamaluj [8]3 years ago
4 0

Answer:

The true statement is:  The probability that a randomly selected player on Team C is 10 years old is \frac{5}{16}.

Step-by-step explanation:

According to the table the total number of 10 years old players on Team C is 5 and the total number of all ages players (8, 9 and 10 years old) on Team C is 16, so the probability that a randomly selected player on Team C is 10 years old is 5/16.

denpristay [2]3 years ago
3 0

Answer:

it is c; The probability that a randomly selected player on Team C is 10 years old is Fraction 5 Over 16

Step-by-step explanation:

because edge said that it is correct

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Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. the drive is currently serving a request at cylinder 2,150,
Anni [7]

Answer:

13011, 7586, 7492 , 7424, 9917, and 9137.

Step-by-step explanation:

(1). FCFS is generally based on what is refer to as first come, first serve. That is to say the first one to come will be treated first so, we have that;

FCFS = 81 + 857 + 1084 + 504 + 2256 + 1074 + 1262 + 1167 + 3442 + 1284 = 13011.

(2). (SSTF) Is all about the shortest distance, for example in this question the shortest distance is =

Thus;

Total distance = (2150 - 2069) + (2296 - 2069) + ( 2296 - 2800) +( 3681 - 2800) + (4965 - 3681) + ( 4965 - 1618) + ( 1618-1523) + ( 1523-1212) + ( 1212-544) + ( 544 - 356).

=81 + 227 + 504 + 881 + 1284 + 3347 + 95 + 311 + 668 + 188 = 7586.

(3).SCAN deals with the processing of the nearest request

The distance =146 + 504 +881 + 1284 + 34(4999-4965) + 2930(4999-2069) + 451 + 95 + 311 + 668 +188 = 7492.

(4). LOOK is just like scan.

The distance = 146 + 504 + 881 + 1284 + 2896 + 451 + 95 + 311 + 668 + 188 = 7424.

(5). C-SCAN: this is the kind of scan from one end to the other.

The distance = 146 + 504 +881 +1284 + 34 (4999 - 4965) + 4999 (4999 -0 )+ 356 (356 -0 )+ 188 + 668 + 311 + 95 + 451 = 9917.

(6). C-LOOK : moves in the following order: 2150, 2296, 2800, 3681, 4965, here head moves back 356, 544, 1212, 1523, 1618, 2069.

Thus;

The distance = 146 + 504 + 881+ 1284 + 4609 (4965 - 356) + 188 + 668 + 311+ 95 + 451 = 9137.

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3 years ago
At a concession stand, five hot dog(s) and two hamburger(s) cost $11.75; two hot dog(s) and five hamburger(s) cost $11.00. Find
serg [7]

Answer:

x:hot dogs

y: hamburger

5x + 2y = 11.75

2x + 5y = 11.00

10x + 4y = 23.50

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y = $1.50 each hamburger

2x + 5(1.50)= 11.00

2x + 7.50 = 11.00

2x = $3.50

x = $1.75 each hot dog

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