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3 years ago

Help ASAP plz real answers only

Mathematics

1 answer:

Musya8 [376]3 years ago

7 0

Yes they are, because when you use ASA, it works

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HELP HELP HELP HELP HELP!!!!

Nutka1998 [239]

Answer:

5)m=11/10

6)m=-17/2

7)m=18.13

8)m=-26/9

BTW The M is an EXAMPLE

Step-by-step explanation:

4 0

3 years ago

ASAP PLEASE IM BEGGING A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxe

almond37 [142]

Answer:

I KNOW IT I HAD IT LAST YEAR

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Would this expression:

Ratling [72]

The given expression is a perfect square trinomial.

<h3>How to classify the given expression?</h3>

Here we have the expression:

$(x^2 - 16)^2$

Notice that we can rewrite it as:

$(x^2 - 4^2)^2$

Then we can see that inside the parenthesis we have a difference of squares, but it is squared, so if we define:

$x^2 = a\\4^2 = b$

We will have:

$(a - b)^2 = a^2 + -2ab + b^2 = (x^2)^2 - 2*(4^2)*(x^2) + (4^2)^2$

Which is in fact, a perfect square trinomial.

If you want to learn more about perfect squares:

brainly.com/question/1538726

#SPJ1

4 0

2 years ago

Evaluate 11.5s + 10.7t when s = 7 and t = 8 .

Elenna [48]

Answer:

166.1

Step-by-step explanation:

It would become 11.5 * 7 + 10.7 * 8 = 80.5 + 85.6 = 166.1

6 0

3 years ago

The parents of three children, ages 1, 3, and 6, wish to set up a trust fund that will pay X to each child upon attainment of ag

ehidna [41]

Answer:

The equation of <em>Z</em> is: $Z=X(v^{17}+v^{15}+v^{12})+Y(v^{20}+v^{18}+v^{15})$

Step-by-step explanation:

The first child is of age 1 year.

Then the amount invested for the 1-year old is: $Xv^{17}+Yv^{20}$

The second child is of age 3 years.

Then the amount invested for the 3-year old is: $Xv^{15}+Yv^{18}$

The third child is of age 6 years.

Then the amount invested for the 6-year old is: $Xv^{12}+Yv^{15}$

The one-time investment will be:

$Z=Xv^{17}+Yv^{20}+Xv^{15}+Yv^{18}+Xv^{12}+Yv^{15}\\=X(v^{17}+v^{15}+v^{12})+Y(v^{20}+v^{18}+v^{15})$

6 0

3 years ago