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3 years ago

Please help I need it ASAP or I can't graduate!

Mathematics

1 answer:

Stella [2.4K]3 years ago

8 0

This wouldn't happen in real life, as Dawdling somehow started halfway through. However, the slope for Prompt appears to be 1 and the slope for Dawdling appears to be 0.

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Please help if you can ty!!

Slav-nsk [51]

To travel 13 mph it would take roughly 8.2 minutes !

6 0

3 years ago

Add 3×+8y-12zand5x-7y+15z help meee

inn [45]

3x+5x+12z+15z+8y+7y

8x+17z+15y

4 0

3 years ago

A kitten’s mass at birth was 0.09 kilogram. The kitten gained approximately 0.084 kilogram each week. After how many weeks is th

Naddika [18.5K]

A kitten’s mass at birth was 0.09 kilogram. The kitten gained approximately 0.084 kilogram each week. After how many weeks is the kitten’s mass 1.098 kilograms?

5 0

3 years ago

P- 24/n = 30/100 What’s N? Z- n/4 = 18/72 What’s N?

Vilka [71]

Answer:

Z: n = 1 P: n =80

Step-by-step explanation:

cross multiple what you can and divide it by the last number left to find n

8 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

4 years ago