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spin [16.1K]
3 years ago
5

Please help I need it ASAP or I can't graduate!

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0
This wouldn't happen in real life, as Dawdling somehow started halfway through. However, the slope for Prompt appears to be 1 and the slope for Dawdling appears to be 0. 
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A rectangle measured 2 ⅔ inches by 1 5/9 inches what is its area
andre [41]

Answer:

4 4/27 sq inches

Step-by-step explanation:

the area is 2⅔ × 1 5/9 = 8/3 × 14/9

= 112/27 = 4 4/27

5 0
3 years ago
NEED HELP ASAP PLEASE HELP
marusya05 [52]
It's C.......................
3 0
3 years ago
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Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
3 years ago
Зу+9=14
Anon25 [30]

Answer:

Constant(s) = 14,9

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Variable = y

6 0
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might be C not sure though

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