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andre [41]
3 years ago
11

A recipe requires 5/6 of a cup of sugar. If mrs.Marina is going to make one half of the recipe, how much sugar does she need

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

Half\ of\ the\ recipe\ requires\ \frac{5}{12}\ of\ a\ cup\ of\ sugar.

Step-by-step explanation:

As given

A\ recipe\ requires\ \frac{5}{6}\ of\ a\ cup\ of\ sugar.

i.e

\frac{5}{6}\ cup\ of\ sugar = 1\ recipe

As the  mrs.Marina is going to make one half of the recipe .

Thus\ multiply\ above\ by\ \frac{1}{2}.

We get

\frac{5\times 1}{6\times 2}\ cup\ of\ sugar = \frac{1}{2}\ recipe

solving the above

\frac{5}{12}\ cup\ of\ sugar = \frac{1}{2}\ recipe

Therefore\ half\ of\ the\ recipe\ requires\ \frac{5}{12}\ of\ a\ cup\ of\ sugar.



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Jeremy bake 9 cakes for the bake sale he put 2 cups of powder surger evenly on the tops
yanalaym [24]
If Jeremy has 2 cups of sugar, and evenly distributes it onto 9 cakes, he would have put .222 (repeating 2) cups of cake on each cake. 
4 0
3 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C

Solve for x(t).

\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}

3 0
2 years ago
Find all the zeroes of the equation. x4 – 6x2 – 7x – 6 = 0
NeX [460]

Answer:

-2, 3,  -0.5 + 0.866i,   -0.5 - 0.866i.

Step-by-step explanation:

As the last term is -6 , +/- 2 , +/- 3 are possible zeroes.

Try 2:-

(2)^4 - 6(2)^2 - 7(2) - 6 = -28 so  2 is not a zero.

3:-

(3)^4 - 6(3)^2 - 7(3) - 6 = 0 so 3 is a zero.

(-2)^4 - 6(-2)^2 - 7(-2) - 6 =  0 so -2 is also a zero.

Divide the function by (x +2)(x - 3),  that is  x^2 - x - 6

gives  x^2 + x + 1

x^2 + x + 1

So we have x^2 + x + 1 = 0

x =  [-1 +/- √(1^1 - 4*1*1)] / 2

= -1 + √(-3) / 2 , - 1 - √(-3)  / 2.

= -0.5 + 0.866i, -0.5 - 0.866i

7 0
3 years ago
Select the correct answer.
abruzzese [7]

Solution's

radius =6

Circumference=?

(21π\2)

21* 6/2

=63

6 0
3 years ago
Read 2 more answers
Not sure which one is it<br><br>plz help
viva [34]
The last one is correct answer
7 0
3 years ago
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