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Mekhanik [1.2K]
2 years ago
13

Most viruses.... can use host machinery to produce more of themselves are persistent and innocuous within host cells switch betw

een pathogenic and non-pathogenic modes of existence kill the cell they infect are rarely found in the natural world.
Biology
1 answer:
Novay_Z [31]2 years ago
7 0

Answer: Most viruses can use host machinery to produce more of themselves

Explanation:

Since viruses carry out no metabolism themselves, they rely solely on the living cells of the host (organism they infect) to replicate and spread from cell to cell.

Thus, viruses do not kill the cells they infect since they need them, and use them to replicate more offsprings

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Large doses of antibiotics given to fight an infection are likely to destroy bacteria that produce vitamin K. In which digestive
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The nurse is caring for a client who has an infection spread by respiratory droplets and is in droplet precautions. the client a
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Why do living things depend on diffusion?
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3 years ago
Which element IS found in proteins, but NOT found in carbohydrates?
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5 0
3 years ago
You discover a population of mustard plants and find it to be at Hardy–Weinberg equilibrium with respect to the R locus. Suppose
natulia [17]

Answer:

The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:

p + q = 1

r-6 + R = 1  

0.2 + 0.8 = 1

Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64

The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04

And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32

5 0
3 years ago
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