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mixas84 [53]
3 years ago
14

The first idea for a communications network was called

Computers and Technology
2 answers:
Dominik [7]3 years ago
6 0

Answer:

the galactic network

Explanation:

seropon [69]3 years ago
3 0

Answer:

The first idea for a communications network was called ARPANET

Explanation:

This serves as the base of internet and other world-wide connections we make today. This was developed by ARPA by the direction given by U.S Government. First they connected four different computers in the university. The history says that, internet was first used by Defense team to pass secret messages from one place to another place.

ARPA has set various rules for communication with which all the new protocols where developed. It was connecting system through telephone line and now we are in the world of “wifi”.

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The answer would be a C class fire extinguisher. 
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Given that k refers to a non-negative int value and that t has been defined and refers to a tuple with at least k+1 elements, wr
Rus_ich [418]

Answer:

The expression is "t[k]".

Explanation:

In the question, it is defined that variable k refers to positive integer and variable t refers to a tuple that holds at least k+1 element. The expression for defining the kth element of t is t[k].

  • Where variable t is tuple that collects a sequence of immutable (in-built) Python objects. To define tuple we use the parentheses.
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Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

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       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

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       int misc = 0;

       String punctuation = ".!,?";

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       for (int k = 0; k < as.length(); k++){

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           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

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   }

   

}

This is one example of how it could be done.

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for(int z=1;z<=length;z++){

if(array[i+z]!=output[y]){

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//output the array

for(int o=0;o<y;o++)

System.out.println(output[o];

3 0
3 years ago
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