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3 years ago

Why does the PC send out a broadcast ARP prior to sending the first ping request

1 answer:

5 0

Since the ARP broadcast is utilized to request the MAC address of the Host with the IP address contained in the ARP, the PC needs to know the destination of MAC address before it can produce the frame header for the particular PING requested, before it can send a PING to a host.

You might be interested in

Large and powerful computer capable of processing and storing large amounts of business data

Nata [24]

Answer:

True

Explanation:

but no need to be large physically ;)

the important point is the computer must have a proper specification to process a large amount of data

6 0

3 years ago

Which is not covered under the Computer Access Device and Computer Fraud and Abuse Act (CADCFA)? unauthorized use of federal com

Mazyrski [523]

Answer:

The correct answer to the following question is "Typewriters".

Explanation:

CADCFA seems to be the very first provision of federal laws to specifically concentrate on computer assault. These clauses continued to allow corporations to prosecute unjust workers for compensation for the misuse of confidential or sensitive information.

Even though we all agree that sometimes a federal worker uses the typewriters in the abundance of power, that's why it's not protected by that same act.
The other options are incorrect because they are all known and are covered for that given CADCFA act.

5 0

3 years ago

Indicate whether the following actions are the actions of a person who will be a victim, or will not be a victim, of phishing at

Zepler [3.9K]

Answer:

Phishing Victim

Explanation:

Replying to this email could make you a victim of a phishing scam. Phishing attacks are common challenges on security that internet users are faced with. It could lead to others getting hold of sensitive information like your password or bank details. email is one way the hackers used to get this information. replying to such an email could lead one to an unsecure website where information could be extracted

4 0

3 years ago

The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an

oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

The memory size is 1 Giga Bytes which is equal to $2^{30}$

$\texttt{Number of address bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ Number of addresses}\\\\ \ \ \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2^{30}= 1073741824$

B) $\texttt{I \ \ \ Opcode \ \ \ Register address \ \ \ Immediate operand \ \ \ Memory address}\\\\\\\textt{1 \ bit \ \ \ \ \ \ 128 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30 \ bits}\\\\\\$ $= 2^7 \\\\ = 7 \ bits$

calculating the register Bits:

$= 64-(1+7+24+30)\\\\=64 -62\ \ bits\\\\= 2\ \ bits\\$

Immediate value size while merging the additional benefit with the address field:

$= 2^{24} + 2^{30}\\\\= 2^{54}\\\\$ $\texttt{Range before combining(-,+) 24 bits \ \ \ \ \ \ Range after combining( -,+)54bits}\\\\$ $\textt{-2^{12} from + (2^{12}-1) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2^{27} from + (2^{27}- 1)}$

$= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27$

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0

3 years ago

Can you help me correct a sentence?

tamaranim1 [39]

Number 2 is your answer!!!!

6 0

3 years ago