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4 years ago

A triangular Pyramid has a base of 10 square feet and a height of 30 feet. What is the volume of the pyramid?

Mathematics

1 answer:

kondor19780726 [428]4 years ago

8 0

Answer: volume of pyramid is

100 ft.3

Step-by-step explanation:

The formula for determining the volume of triangular Pyramid is expressed as

Volume = 1/3AH

Where

A represents the area of the triangular base of the pyramid

H represents the height of the pyramid.

The triangular Pyramid has a base of 10 square feet and a height of 30 feet. Therefore,

Volume = 1/3 × 10 × 30 = 100 cubic feet

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Answer:

The values for the given function f is defined by $f(x)=\frac{1}{2}x$ is

a) $f(0)=0$ ,

b) $f(18)=9$ and

c) $f(-18)=-9$

Step-by-step explanation:

Given that the function f is defined by $f(x)=\frac{1}{2}x$

Now to find the value of f(0), f(18) and f(-18)

Now take f(0)

Put x=0 in the given function $f(x)=\frac{1}{2}x$ we get

$f(0)=\frac{1}{2}(0)$

$=0$

Therefore $f(0)=0$

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$f(18)=\frac{1}{2}(18)$

$=9$

Therefore $f(18)=9$

Put x=-18 in the given function $f(x)=\frac{1}{2}x$ we get

$f(-18)=\frac{1}{2}(-18)$

$=-9$

Therefore $f(-18)=-9$

The values for the given function f is

a) $f(0)=0$ ,

b) $f(18)=9$ and

c) $f(-18)=-9$

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3 years ago

Read 2 more answers

Find the Value of Sin A rounded to the nearest hundredth, if necessary.

leonid [27]

Step-by-step explanation:

In trigonometry, the law of sines is an equation that relates the length of the sides of a triangle (any type of triangle) to the sines of its angles. This is expressed mathematically as

$\displaystyle\frac{a}{\sin \alpha} \ = \ \displaystyle\frac{b}{\sin \beta} \ = \ \displaystyle\frac{c}{\sin \gamma}$ ,

where $a$ , $b$ , and $c$ are the lengths of the sides of the triangle and $\alpha$ , $\beta$ , and $\gamma$ are the opposite angles (as shown in the figure below). Likewise, the law is sometimes written as it reciprocals,

$\displaystyle\frac{\sin \alpha}{a} \ = \ \displaystyle\frac{\sin \beta}{b} \ = \ \displaystyle\frac{\sin \gamma}{c}$ .

Therefore,

$\displaystyle\frac{\sin A}{BC} \ = \ \displaystyle\frac{\sin B}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sin B \ \times \ BC}{AC} \\ \\ \\\sin A \ = \ \displaystyle\frac{\sin \left(90^{\circ}\right) \ \times \ \sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \dsiplaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$

Alternatively, you can solve this question using the definition of the trigonometric function sine. For the angle $\theta$ in the figure below,

$\sin \theta \ = \ \displaystyle\frac{\text{opposite}}{\text{hypothenuse}}$ .

Therefore,

$\sin A \ = \ \displaystyle\frac{BC}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$