6 times 12 is 72 so 14 times 12 would be 168 if that is what you are looking for. So for that y=168 :-)
Answer:
1.43
Step-by-step explanation:
I am sorry if i am wrong
Answer:
The 95% confidence interval for population mean is (18.19, 23.81).
Step-by-step explanation:
The confidence interval for population mean using the Student's <em>t</em>-distribution is:

Given:

The critical value of <em>t</em> for <em>α </em>= 0.05 and degrees of freedom, (<em>n</em> - 1) = 19 is:

Compute the 95% confidence interval for population mean as follows:

Thus, the 95% confidence interval for population mean is (18.19, 23.81).
56 is the answer :)) your welcome