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Naddika [18.5K]
2 years ago
13

Rewrite each equation in exponential form and evaluate. Log5(625)^x=?

Mathematics
1 answer:
Savatey [412]2 years ago
7 0
5^?=625^x, x=1/4

To rewrite in exponential form, the equation would be 5^?=625^x. From here, the bases need to be set equal. Since the fourth root of 625 is 5, the new equation becomes 625^1/4=625^x (625^1/4 is the same as the fourth root of 624). Now that the bases are the same, you can just solve for the variables, which become 1/4=x. Hope this helps :)
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Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

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