Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
Answer: Our required probability would be 0.9641.
Step-by-step explanation:
Since we have given that
Number of hours he works a day = 8
So, Number of minutes he worked in a day = 
Number of calls = 220
So, Average 
Standard deviation 
Mean = μ = 2.0 minutes
Standard deviation = σ = 1.5 minutes
Using the normal distribution, we get that
So, the probability that Albert will meet or exceed his quota would be
Hence, our required probability would be 0.9641.
This is easy. You just add all the like terms
Rs 9600 pls give Brainlyest
