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2 years ago

I need help please ?!!

Mathematics

1 answer:

melomori [17]2 years ago

3 0

the answer is b because the answer for both of them is -39. you might also want to look into the sign rules in algebra bb :)

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( please help!! )Find the slope of each line

marysya [2.9K]

Answer:

-2/5

Step-by-step explanation:

Slope is rise over run according to my former algebra teacher, but I learned it differently (still correct tho).

The first moves 2 units down so negative 2, and moves 5 units right, so -2/5 since the rise is -2, and run is 5.

The second one moves 2 x-units for every 1 y-unit, so the slope is 2,

5 0

2 years ago

Find the value of x

Hunter-Best [27]

Answer:

35.8 deg

Step-by-step explanation:

a/sin A = b/sin B

24/sin x = 39/sin 71.8

sin x = (24 * sin 71.8)/39

sin x = 0.584598

x = sin^-1 0.584598

x = 35.8 deg

6 0

2 years ago

Another one, soon it'll be over (i hope)

maks197457 [2]

Answer:

24. 8 x 3.....................

6 0

2 years ago

Read 2 more answers

Evaluate 7³=7•7•7=343

ivanzaharov [21]

343=343=343
I am pretty sure this is the answer to the problem

4 0

2 years ago

Read 2 more answers

g A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam. We ar

BaLLatris [955]

Answer:

The test statistic is $z = 1.25$

Step-by-step explanation:

We are interested in determining whether or not the proportion of the student who experience anxiety during the exam is significantly more than 80%.

At the null hypothesis, we test if the proportion is 80%, that is:

$H_0: p = 0.8$

At the alternate hypothesis, we test if the proportion is more than 80%, that is:

$H_a: p > 0.8$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

80% is tested at the null hypothesis:

This means that $\mu = 0.8, \sigma = \sqrt{0.2*0.8} = 0.4$

A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam.

This means that $n = 100, X = \frac{85}{100} = 0.85$

The test statistic is

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.85 - 0.8}{\frac{0.4}{\sqrt{10}}}$

$z = 1.25$

The test statistic is $z = 1.25$

4 0

2 years ago