For this case we have:
By properties of the radicals 
So:
.
Now, for power properties we have:
Thus, 
So:
in its radical form
Answer:
in its simplest form.
in its radical form
1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Answer:
The answer is B
Step-by-step explanation:
I got it right on the test
Ohms law states V=IR
I is current and R is resistance
We are given V=120 and R=30
Therefore 120=I*30 or I=40A
The area is found by multiplying the length by the width.
The original area = 60 x 40 = 2,400 square feet
He wants to make it 1/2 that size, so the new size would be 2,400 / 2 = 1,200 square feet.
To find the length divide the new area by the new width:
1,200 / 30 = 40
The new length should be 40 feet.
