4x^5 + 3x + 1...the ^5 makes it a fifth degree....and the leading coefficient is 4
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<u>Answer:
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The point-slope form of the line that passes through (1,-5) and is parallel to a line with a slope of 1 is y + 5 = x – 1
<u>Solution:
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The point slope form of the line that passes through the points and parallel to the line with slope “m” is given as
---- equation 1
Where “m” is the slope of the line. and are the points that passes through the line.
From question, given that slope “m” = 1
Given that the line passes through the points (1,-5). Hence we get and
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope 1 can be found out.
y – (-5) = 1(x – 1)
y + 5 = x – 1
hence the point slope form of given line is y + 5 = x – 1