It can be a transversal kind of intersecting.....
Answer:
116 divide 4=m
4x m =116
Step-by-step explanation:
Answer:
The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.
The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm
The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.