Answer:
it's 1 dekameter (dam) = 10 meters you need to use that
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
228.5 I believe. 14/49 is 3.5. 18+7 is 25x9 is 225. 225+3.5 would be 228.5
Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
Answer:
Step-by-step explanation:
<u>Use the slope formula:</u>
10.
- m = (6.24 - 3.27)/(5 - 2) = 2.97/3 = 0.99
11.
- m = (240 - 360)/(3 - 1) = -120/2 = -60
12.
- m = (8.84 - 6.09)/(7 - 2) = 2.75/5 = 5.5
