Find perimeter of rectangle if length is 2x+8 width is 5x-2
2 answers:
Step-by-step explanation:
perimeter is the distance round. Add all the algebras
2x+8+5x-2+2x+8+5x-2
{<em>c</em><em>o</em><em>m</em><em>b</em><em>i</em><em>n</em><em>e</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>i</em><em>k</em><em>e</em><em> </em><em>t</em><em>e</em><em>r</em><em>m</em><em>s</em><em>}</em>
P= 14x+12
Answer:
P=(a+b)*2
P=(2x+8+5x-2)*2=(7x+6)*2=14x+12
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Y = 3x - 7
just find the slope then use two point and point slope form to solve for slope intercept form
Answer:
width=1005 length=1335
Step-by-step explanation:
If the length is 330 ft greater than you would subtract 330 from 2340 and then divide 2010 by 2 to get 1005 then add 330 to 1005 and get 1335
