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Aloiza [94]
3 years ago
13

Find the 77th term of the arithmetic sequence -7, -2, 3, ...

Mathematics
1 answer:
sukhopar [10]3 years ago
3 0

Answer:

373

Step-by-step explanation:

first you find the difference between the first two numbers so we do -7 minus -2=-5 then plug it in -7+5=-2 now plug in 5 for the next two numbers -2+5=3 so now we know the rule is +5 now we do 5*76=380 then we do -7+380=373

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Simplify using the distributive property
ad-work [718]

Answer:

3/5 is the number that can be distributed across two terms inside parentheses.

you might not need it but:

x = 5

Step-by-step explanation:

<u>3/5(x - 10)</u> = 18 - 4x - 1

using distributive property, open the parentheses:

<u>3/5x - 6 </u>= 18 - 4x - 1

Simplify:

3/5x + 4x = 17 + 6

4⅗x = 23

x = 5

8 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3 / (x^-2y^2)^-4]^-2
True [87]
<span>The answer is (x</span>¹⁰<span>y</span>¹⁴<span>)/729.

Explanation:
We can begin simplifying inside the innermost parentheses using the properties of exponents. The power of a power property says when you raise a power to a power, you multiply the exponents. This gives us

[(3</span>³<span>x</span>³<span>y</span>⁻¹⁵<span>)/(x</span>⁸<span>y</span>⁻⁸<span>)]</span>⁻²<span>.

Negative exponents tell us to "flip" sides of the fraction, so within the parentheses we have
[(3</span>³<span>x</span>³<span>y</span>⁸<span>)/(x</span>⁸<span>y</span>¹⁵<span>)]</span>⁻²<span>.

Using the quotient property, we subtract exponents when dividing powers, which gives us
(3</span>³<span>/x</span>⁵<span>y</span>⁷<span>)</span>⁻²<span>.

Evaluating 3</span>³<span>, we have
(27/x</span>⁵<span>y</span>⁷<span>)</span>⁻²<span>.

Using the power of a power property again, we have
27</span>⁻²<span>/x</span>⁻¹⁰<span>y</span>⁻¹⁴<span>.

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4 0
3 years ago
Read 2 more answers
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Mrac [35]

The reciprocal of a number x is 1/x.

Let x = 1000

The reciprocal is 1/1000.

7 0
3 years ago
Read 2 more answers
Worth 12 Points, i spent 24
rewona [7]

Answer:

  \displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}

Step-by-step explanation:

The relevant rule of exponents is ...

  (a^b·c^d)^e = a^(be)·c^(de)

Then ...

  (m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

  = m^(35/12)·n^(-28/15)

__

Since you want positive rational exponents, you can write this as ...

  = m^(35/12)/n^(28/15)

6 0
3 years ago
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jarptica [38.1K]

Answer:

B , there are infinite solutions.

Step-by-step explanation:

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8 0
3 years ago
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