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Charra [1.4K]
3 years ago
9

Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. 254

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

614°, -106°

Step-by-step explanation:

Coterminal angles are angles in standard position, that is, angles with the initial side on the positive x-axis, that have a common terminal side.

Coterminal angles can be found by adding or subtracting 360° to the original angle.

Let's consider the angle 254°.

If we add 360°, we have 254° + 360° = 614°. This is a positive coterminal angle.

If we subtract 360°, we have 254° - 360° = -106°. This is a negative coterminal angle.

Ksenya-84 [330]3 years ago
4 0
360-254= -106
One angle is 254 and the other -106
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Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

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Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

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Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

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The length and width of a rectangle are ( 2x -5) and ( 3 x +4) What is the Perimeter?
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Answer:

\fbox{ \sf{Perimeter \: of \: a \: rectangle = 10x - 2}}

Step-by-step explanation:

\star{ \sf{ \:  \: Length \: of \: a \: rectangle ( l )  = (2x - 5) }}

\star{ \sf{ \: Width \: of \:  a \: rectangle ( w ) = (3x + 4)}}

\star{ \sf{ \:  \: Perimeter \: of \: a \: rectangle =  ?}}

\boxed{ \bold{  \sf{Perimeter \: of \: a \: rectangle = 2(l + w)}}}

\hookrightarrow{ \sf{Perimeter \: of \: a \: rectangle = 2(2x - 5 + 3x + 4)}}

\text{Step \: 1 : \: Collect \: like \: term}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base}

\hookrightarrow{ \sf{2(2x  + 3x - 5 + 4)}}

\hookrightarrow{ \sf{2(5x - 5 + 4)}}

\text{Step \: 2  \: :  \: Subtract \: 4 \: from \: 5}

\text{Remember !\:  : the \: negative \: and \: positive \: integers \: are \: always \: subtracted \: but \: posses \: the \: sign \: of \: the \: bigger \: integer}

\hookrightarrow{ \sf{2(5x - 1)}}

\text{Step \: 3 \:  :  \: Distribute \: 2 \: through \: the \: parentheses}

\hookrightarrow{ \sf{2 \times 5x - 2 \times 1}}

\hookrightarrow{ \sf{10x - 2}}

\sf{∴ \: The \: perimeter \: of \: a \: rectangle = 10x - 2}

\text{Hope \: I \: helped !}

\text{Best \: regards ! }

~\text{TheAnimeGirl}

5 0
3 years ago
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