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Charra [1.4K]
2 years ago
9

Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. 254

Mathematics
2 answers:
bixtya [17]2 years ago
8 0

Answer:

614°, -106°

Step-by-step explanation:

Coterminal angles are angles in standard position, that is, angles with the initial side on the positive x-axis, that have a common terminal side.

Coterminal angles can be found by adding or subtracting 360° to the original angle.

Let's consider the angle 254°.

If we add 360°, we have 254° + 360° = 614°. This is a positive coterminal angle.

If we subtract 360°, we have 254° - 360° = -106°. This is a negative coterminal angle.

Ksenya-84 [330]2 years ago
4 0
360-254= -106
One angle is 254 and the other -106
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Step-by-step explanation:

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3 years ago
Dario divides 4/6 yard of rope equally into 1/12 yard pieces for a craft project.How many pieces of rope does Dario have?Use a n
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Answer:

Eight pieces

Step-by-step explanation:

Create a number line running from 0 to 4/6.

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Starting at zero, move to 4/6 on the number line and count the number of pieces as you go.

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5 0
3 years ago
Read 2 more answers
How do you solve it?
Elis [28]

At heart we're being asked for a line through two points,


(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})


In general the line through (a,b) and (c,d) is


(y-b)(c-a)=(x-a)(d-b)


Check that you understand why both (a,b) and (c,d) are on this line.


Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,


(v - 355)(49 - 40) = (T - 40)(360 - 355)


9(v - 355) = 5(T - 40)


v-355 = \frac 5 9 T - \frac{200}{9}


v= \frac 5 9 T - \frac{200}{9} + 355


v= \frac 5 9 T + \frac{2995}{9}


That's our answer; let's check it.


When T=40, v = (5/9)40 + (2995/9) = 355 good


When T=49, v= (5/9)49 + (2995/9) = 360 good




7 0
2 years ago
A radioactive substance decays exponentially. A scientist begins with 190 milligrams of a radioactive
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Step-by-step explanation:

y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}

6 0
2 years ago
Which of the following situations results in an answer of 23 ? Select three that apply.
Nata [24]

Answer:

The first, second, and fourth questions.

Step-by-step explanation:

None of these result in an answer of 23, so I'm assuming that you meant 2/3.

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4 0
2 years ago
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