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matrenka [14]
3 years ago
6

GIVING LOTS OF POINTS AND BRAINLEST

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0

Answer:

a circle centered at (3,-1) with radius 5.

Ulleksa [173]3 years ago
6 0

Answer:

The given equation represents a circle centered at (3,-1) with radius 5.

Step-by-step explanation:

The given equation is

(x-3)^2+(y+1)^2=25            ....(1)

The higher degree of both variables is 2, therefore the equation does not represents a parabola because in case of parabola the degree of both variables are not same.

The given equation is in the standard form of a circle.

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2         .... (2)

Where, r is the radius of circle and (h,k) is the center of circle.

On comparing equations (1) and (2), we get

h=3

k=-1

r=5

Therefore the center of the circle is (3,-1) and radius of the circle is 5.

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2 years ago
For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of
mihalych1998 [28]

Answer:

V=196in^3

Step-by-step explanation:

The volume of a pyramid is:

V=\frac{A_{b}h}{3}

where A_{b} is the area of the base and h is the height (the perpendicular measurement between base and highest point, not the slant height)

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A_{b}=l^2

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Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

hypotenuse^2=leg1^2+leg2^2

substituting our values, and indicating that leg 1 is height h:

(10in)^2=h^2+(4in)^2

100in^2=h^2+16in^2

and solving for the height:

h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in

and finally we calculate the volume using this height and the area of the base:

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rounding to the nearest cubic inch: V=196in^3

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3 years ago
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Q and R are independent events. P(Q) = 0.4; P(Q AND R) = 0.08. Find P(R).
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