GIVING LOTS OF POINTS AND BRAINLEST
2 answers:
Answer:
The given equation represents a circle centered at (3,-1) with radius 5.
Step-by-step explanation:
The given equation is
....(1)
The higher degree of both variables is 2, therefore the equation does not represents a parabola because in case of parabola the degree of both variables are not same.
The given equation is in the standard form of a circle.
The standard form of a circle is
.... (2)
Where, r is the radius of circle and (h,k) is the center of circle.
On comparing equations (1) and (2), we get
Therefore the center of the circle is (3,-1) and radius of the circle is 5.
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9514 1404 393
Answer:
(a) none of the above
Step-by-step explanation:
The largest exponent in the function shown is 2. That makes it a 2nd-degree function, also called a quadratic function. The graph of such a function is a parabola -- a U-shaped curve.
The coefficient of the highest-degree term is the "leading coefficient." In this case, that is the coefficient of the x² term, which is 1. When the leading coefficient of an even-degree function is positive, the U curve has its open end at the top of the graph. We say it "opens upward." (When the leading coefficient is negative, the curve opens downward.)
This means the bottom of the U is the minimum value the function has. For a quadratic in the form ax²+bx+c, the horizontal location of the minimum on the graph is at x=-b/(2a). This extreme point on the curve is called the "vertex."
This function has a=1, b=1, and c=3. The minimum of the function is where ...
x = -b/(2·a) = -1/(2·1) = -1/2
This value is not listed among the answer choices, so the correct choice for this function is ...
none of the above
__
The attached graph of the function confirms that the minimum is located at x=-1/2
_____
<em>Additional comment</em>
When you're studying quadratic functions, there are few formulas that you might want to keep handy. The formula for the location of the vertex is one of them.
