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Andre45 [30]
3 years ago
11

Find the sum of-10x^2-x+6 and 10x^2-5

Mathematics
1 answer:
Sindrei [870]3 years ago
4 0

Answer:

=-10x^2-x+6adn

Step-by-step explanation:

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Find approximate solution for the equation in the interval 0<_ x <_ pi. round to three decimal places. tanx=5 sin x
timofeeve [1]

Answer:

d. 0, 1.369

Step-by-step explanation:

Given:

The equation is: \tan x =5\sin x................(0\leq x\leq \pi)

Adding -5\sin x on both sides, we get

\tan x - 5\sin x=0

Using the identity \tan x=\frac{\sin x}{\cos x}, we get

\frac{\sin x}{\cos x}-5\sin x=0

Factoring out \sin x, we get

\sin x(\frac{1}{\cos x}-5)=0\\\\\therefore \sin x=0\ or\ \frac{1}{\cos x}-5=0\\\\x=\sin^{-1} (0)\ or\ \cos x=\frac{1}{5}\\\\x=0\ or\ x=\cos^{-1} (\frac{1}{5})\\\\x=0\ or\ x=1.3694\approx 1.369(\textrm{Round to 3 decimal places})

Therefore, the solution of the given equation is either 0 or 1.369.

The correct choice is d.

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3 years ago
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