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goldfiish [28.3K]
3 years ago
6

Sara and Sam are each working on a science project in which they need to research the individual masses of the nine planets (inc

luding the dwarf planet Pluto as the ninth planet). Sara completes her data for the planets' masses in kilograms while Sam's data is in milligrams.
Look at picture.


Approximate how many times greater Saturn's mass is than Mercury's.

A) 200,000
B) 2,000,000
C) 2,000
D) 20,000

Mathematics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

2000 times

Step-by-step explanation:

Given

Sara:

Mercury = 3.302 * 10^{23

Saturn = 5.685 * 10^{26

Sam:

Mercury = 3.302 * 10^{29

Saturn = 5.685 * 10^{32

To determine the number of times, the mass of Saturn is greater than the mass of Mercury, we simply do the following:

Times = \frac{Saturn}{Mercury}

Using Sara's measurement; this gives:

Times = \frac{5.685 * 10^{26}}{3.302 * 10^{23}}

Apply law of indices

Times = \frac{5.685 * 10^{26-23}}{3.302}

Times = \frac{5.685 * 10^3}{3.302}

Times = 5.685/3.302 * 10^3

Times = 1.72 * 10^3

Approximate

Times = 2 * 10^3

Times = 2000

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3 years ago
Hello I need help on it ​
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Answer:

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The volume of a cube is 216 ft. What is the length of a side?
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Step-by-step explanation:

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Read 2 more answers
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
22.Island A is 160 miles from island B. A ship captain travels 170 miles from island A and then finds that he is off course and
bixtya [17]

we know that

Applying the law of cosines: 


c² = a² + b² - 2abcos(C) 

where: 

a,b and c are sides of the triangle and C is the angle opposite side c 

let

a=170 mi

b=200 mi

c=160 mi

that is 

160² = 170² + 200² - 2(170)(200)cos(C) 


solve for C 


25,600 = 28,900 + 40,000 - 68,000cos(C) 

25,600 - 28,900 - 40,000 = -68,000cos(C) 

-43,300=-68,000cos (C)

cos (C)=0.6367

C=arc cos(0.6367)--------> C=50.45°


hence, 

he should turn in the direction of island b by

180 - 50.45 = 129.55 degrees


the answer is

129.55 degrees

6 0
4 years ago
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