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VARVARA [1.3K]
3 years ago
15

URGENT! BRAINLIEST ANSWER!!!

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

H and I

Step-by-step explanation:

because the sides opposite the angles are congruent. the angles H and I are congruent

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Eliminate the parameter.<br><br><br>x = 5t, y = t + 8 (2 points)
maxonik [38]

Answer: y = \frac{1}{5}x + 8

Step-by-step explanation:

       This is asking us to remove the parameter. In other words, we want an equation with only the relation between x and y, so we need to remove the t. There are a few ways to do this, but I am going to set one equation equal to t and then plug it into the next one.

     Given:

x = 5t

    Divide both sides of the equation by 5:

t = \frac{1}{5}x

     -

    Given:

y = t + 8

    Plug in:

y = (\frac{1}{5}x) + 8

    Answer:

y = \frac{1}{5}x + 8

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2 years ago
5 The graph of a proportional relationship is given along with an equation for a different relationship. Which situation has a g
Shkiper50 [21]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Why is a graphical solution not always appropriate for a system of equations?
BigorU [14]

Answer:

because it may not be suitable for all the time

4 0
3 years ago
What is the inverse of this function? f(x)=-1/2 square root of x+3, x &gt; -3
yuradex [85]

The inverse function of f(x) = -\frac 12\sqrt{x + 3} isf^{-1}(x) = 4x^2- 3

<h3>How to determine the inverse function?</h3>

The function is given as:

f(x) = -\frac 12\sqrt{x + 3}

Rewrite as;

y = -\frac 12\sqrt{x + 3}

Swap the positions of x and y

x = -\frac 12\sqrt{y + 3}

Multiply through by -2

-2x = \sqrt{y + 3}

Square both sides

4x^2 = y + 3

Subtract 3 from both sides

y = 4x^2 - 3

Express as an inverse function

f^{-1}(x) = 4x^2- 3

Hence, the inverse function of f(x) = -\frac 12\sqrt{x + 3} isf^{-1}(x) = 4x^2- 3

Read more about inverse function at:

brainly.com/question/2541698

#SPJ1

3 0
2 years ago
What is 1 whole 3/10 Plus 2 whole 2/5
seraphim [82]

Answer:

1 7/10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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