Question

The length of a rectangular room is 8 feet more than twice the width. If takes perimeter of the room is 124 feet, what are its dimensions?

Answer 1

Hey there! I'm happy to help!

Let's call the length and width L and W respectively.

L=2W+8

2W+2L=124

We plug our value of L into the second equation and solve for W.

2W+2(2W+8)=124

We undo the parentheses with the distributive property.

2W+4W+16=124

Combine like terms.

6W+16=124

Subtract 16 from both sides.

6W=108

Divide both sides by 6.

W=18

We plug this W value into the first equation to solve for L.

L=2(18)+8

L=36+8

L=44

So, the length is 44 feet and the width is 18 feet.

Have a wonderful day! :D