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Zinaida [17]
3 years ago
12

Create a verbal expression with the equation 7(2j + 3 + 2j).

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

28j+21

Step-by-step explanation:

remember to isolate the variable. in this case it would be j. after you do that it should be pretty simple

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Which graph represents the equation -5x+4y>-1?
galben [10]
<h3>Answer: Choice D</h3>

======================================================

Explanation:

The inequality sign has an "or equal to", which means the boundary line will be solid. We can rule out choices B and C because they have dashed boundary lines.

A solid boundary line means that points on the boundary are part of the solution set.

Now let's see what happens when we plug in a point like (x,y) = (4,0). This will tell us how to shade the blue region.

-5x + 4y \ge -1 \\\\-5(4) + 4(0) \ge -1 \\\\-20 \ge -1 \\\\

This is false because -20 is not larger than -1. It's the other way around.

This tells us the point (4,0) is not in the blue shaded region, and it's not on the boundary line either. We can rule out choice A because of this.

The only thing left is choice D, which is the final answer. I recommend plugging a point from this region into the inequality to confirm we have a true statement.

6 0
3 years ago
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ASHA 777 [7]

Answer:

0.8 and 0.9

Step-by-step explanation:

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5 0
3 years ago
Give the domain and range of the relation.
Alex_Xolod [135]

Answer:

Please check the explanation.

Step-by-step explanation:

Finding Domain:

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.

And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.

Thus, the domain is:

D: {-2, -1, 0, 1}       or    D: −2 ≤ x ≤ 1

Finding Range:

We also know that the range of a function is the set of values of the dependent variable for which a function is defined

From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.

And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.

Thus, the range is:

R: {0, 1, 2}   or    R: 0 ≤ y ≤ 2

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