6.1.3
1 answer:
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
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Answer:
50 kg water.
Step-by-step explanation:
We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.
We know that two directly proportional quantities are in form , where y varies directly with x and k is constant of variation.
We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:
Let us find the constant of variation as:
The equation represents the relation between water (y) in a human body with respect to mass of the body (x).
To find the amount of water in a 75-kg person, we will substitute in our given equation and solve for y.
Therefore, there are 50 kg of water in a 75-kg person.