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ra1l [238]
3 years ago
9

18=3-3a what’s the steps

Mathematics
1 answer:
Harrizon [31]3 years ago
6 0

Answer:

a=-5

Step-by-step explanation:

subtract 3 from both sides

15=-3a

divide by -3

a=-5

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1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
4 years ago
What is the probabilit<br> spinning an A?<br> В В<br> A А B<br> СА<br> СС<br> [?]
tekilochka [14]
25% chance because there are 8 total “slices” and there are 2 A’s.
2/8=1/4=25%
7 0
3 years ago
(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selecti
guajiro [1.7K]

Answer:

A) I) 49 teams

II)63 teams

B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

= 21+28

= 49 teams

a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

Girls remaining to choose from 7

Boys remaining to choose from 6

= 1 +7C5 + 6C5

= 1+21+6

= 28 teams

5 0
3 years ago
What is 5 divided by 3/7
DENIUS [597]

it would be 35/3 or 11 2/3
4 0
3 years ago
Craig made 60% of 80 free throw attempts this season how many free throws has he made
almond37 [142]
He has made 48 throws.
.60x80=48
5 0
3 years ago
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