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3 years ago

CAN SOMEONE HELP ME ASAP I DON'T HAVE MUCH TIME!!!!!!!!! 50 POINTS!!!

Mathematics

2 answers:

Rudik [331]3 years ago

6 0

Answer:

The answer is : A

Step-by-step explanation:

I dont think you really care about how to do it. Also, I tried my best. I know you really need this and I really need Brainliest so lets help eachother out.

daser333 [38]3 years ago

6 0

Answer:

Step-by-step explanation:

Geometric sequences have a pattern that is exponential. Because of this, they do not have a constant rate of change using addition or subtraction. Instead, they have a constant rate through multiplication and division called a common ratio. Tank 1 is geometric because as you subtract each y value you get a different value each time. It is not a common difference. But if you divide, you find a common ratio.

Example: 249-300= -60 240/300 = 0.8

192-240 = -48 192/240 = 0.8

etc. Common ratio of 0.8

Arithmetic sequences have a pattern that is linear. Because of this, they do have a constant rate of change using addition or subtraction. This means that the same value is added or subtracted each time to get the next value. It is known as a common difference. Tank 2 is arithmetic because you subtract 40 each time to get the next volume.

Example: 260 - 300 = -40

220 - 260 = -40

Common difference is -40.

This means that only A is correct.

D is not correct because geometric sequences do not have common differences.

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A police officer records the speeds of vehicles on a road. What percent of the vehicles were traveling between 41 and 45 miles p

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Answer:

28%

Step-by-step explanation:

Here is the missing table from the question:

Speed (mph) Number of Vehicles

36-40 2

41-45 14

46-50 18

51-55 12

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Given: A police officer records the speeds of vehicles on a road.

Now, finding the percent of vehicles traveling between 41 and 45 miles per hour.

First, calculating the total number of vehicles.

Total vehicles= $2+14+18+12+4= 50$

Vehicles travelling at speed of 41-45 mph= 14

Formula; percent of vehicles traveling between 41 and 45 mph= $\frac{vehicles\ travelling\ 41-45\ mph}{Total\ number\ of\ vehicles} \times 100$

⇒ Percent of vehicles traveling between 41-45 mph= $\frac{14}{50} \times 100= 14\times 2$

∴ Percent of vehicles traveling between 41-45 mph is 28%

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3 years ago

In ABC, CT is a median. What is the measure of AB?

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Answer:

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Step-by-step explanation:

the median CT bisects the side AB at T , then

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2x + 9 = 21 ( subtract 9 from both sides )

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The answer:

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