Answer:
y = -x +4
Step-by-step explanation:
The y-intercept of the line is at +4, so the only viable choice is the last choice.
___
Each of the equations is shown in slope-intercept form:
y = mx + b
where b is the y-intercept, the y-value when x=0. The graph shows that as point (0, 4). So, the equation you're looking for is ...
y = (some x-term) +4
If you want to spend more brain power on the problem, you can compute the slope of the line as ...
m = ∆y/∆x = (1-4)/(3-0) = -3/3 = -1
Now, you know for sure the equation of the line is ...
y = -x +4
£/$340
25% is 1 over 4 and that gives us divide by 4
So what you want to do here is divide 340 by 4 which gives us £/$85
You save around 85 if I’m correct please tell me if I’m wrong :)
Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
Answer:
16 yard line
Step-by-step explanation:
The football team is starting on the 10 yard line. In the first play, they move up to the 24 yard line. Then in the second play, they go back to the 12 yard line since they lost 12 yards. Then in the third play, they gain 4 yards so you add 4 to 12. They end up at the 16 yard line after the third play. This means that they're going to start their fourth play at the 16 yard line.
Answer:
20
Step-by-step explanation:
