Question

"A turtle takes 3.5 minutes to walk 18 m toward the south along a deserted highway. A truck driver stops and picks up the turtle. The driver takes the turtle to a town 1.1 km to the north with an average speed of 12 m/s. What is the magnitude of the average velocity of the turtle for its entire journey

Answer 1

Explanation:

The given data is as follows.

        Velocity of truck = 12 m/s

The turtle has moved in 18 m towards south direction. After that, the truck picks up the turtle towards 1100 m north.

Hence, total displacement will be as follows.

            1100 m - 18 m = 1082 m in the north direction

Time taken by the turtle is 3.5 minutes. Converting time into seconds as follows.

                  $3.5 \times 60 sec$

                   = 210 sec

And, the time taken by the truck is as follows.

             $\frac{1100}{12}$

              = 91.67 sec

Therefore, the total time will be calculated as follows.

                  210 sec + 91.67 sec

                 = 301.67 sec

Now, we will calculate the average velocity as follows.

       Average velocity = $\frac{\text{total displacement}}{\text{total time taken}}$

                                  = $\frac{1082}{301.67}$ m/s

                                  = 3.586 m/s

Thus, we can conclude that average velocity of the turtle for its entire journey is 3.586 m/s.