Answer:1.008 ×10^-14/rJ
Where r is the distance from.which the charge was moved through.
Explanation:
From coloumbs law
Work done =KQq/r
Where K=9×10^9
Q=7×10^-6C
q=e=1.6×10^-19C
Micro is 10^-6
W=9×10^9×7×10^-6×1.6×10^-19/r=100.8×10^-16/r=1.008×10^-14/rJ
r represent the distance through which the force was used to moved the charge through.
Answer:
decreases
Explanation:
Remeber:
There is always inverse relation between frequency and wavelength.
So if one of them increases, other decreases and vice-versa.
f ∝ 1 / λ
Answer:
Angle is 55.52°
and Initial Speed is v=26.48 m/s
Explanation:
Given data
Applying the kinematics equations for motion with uniform acceleration in x and y direction
So
Put the value of v₀ from equation (1) to equation (2)
So
Put that angle in equation (1) or equation (2) to find the initial velocity
So from equation (1)
The distance quantity/ measurement must be squared.
Answer:
C. amount of charge on the source charge.
Explanation:
Electric field lines can be defined as a graphical representation of the vector field or electric field.
Basically, it was first introduced by Michael Faraday and it is typically a curve drawn to the tangent of a point is in the direction of the net field acting on each point.
The number, or density, of field lines on a source charge indicate the amount of charge on the source charge. Therefore, the density of field lines on a source charge is directly proportional to quantity of charge on the source.
