Answer:
Electric field strengh is a measure of the strength of an electric field at a given point in space, equal to the field would induce on a unit electric charge at that point.
<em>Electric</em><em> </em><em>field</em><em> </em><em>strength</em><em> </em>is also known as <em><u>Electric</u></em><em><u> </u></em><em><u>Field</u></em><em><u> </u></em><em><u>Intensity</u></em><em><u> </u></em><em><u>.</u></em><em> </em>
Explanation:
Electric Field is also defined as <em>force</em><em> </em><em>per</em><em> </em><em>charge</em><em>.</em> The unit will be force unit divided by charge unit. In this case, it will be Newton/Coulomb or N/C.
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Answer:
8.33 m/s
Explanation:
v=d/s, velocity = displacement/ time
Answer: a) 31.07 * 10^6 N/C ; b) 11.68 * 10^6 N/C
Explanation: in order to solve this problem we have to use the Coulomb force which is given by:
F=k*q1*q2/r^2
( see attach for details)
Answer:
4.36 seconds
Explanation:
According to the question;
- Force is 550 N
- Mass of the car is 1200 kg
- Velocity of the car is 2.0 m/s
We are needed to find the time the car must the tow track pull the car.
- From Newton's second law of motion;
- Impulsive force, F = Mv÷t , where m is the mass, v is the velocity and t is the time.
Rearranging the formula;
t = mv ÷ F
Thus;
Time = (1200 kg × 2.0 m/s²) ÷ 550 N
= 4.36 seconds
Thus, the time needed to pull the car is 4.36 seconds